Multiplication positive or Negative

Calculator APPS with java

download source of calcultor

Click to DOWNLOAD

Task of Digital Arithmetic

if in the previous post I just completed one section, now I've completed the section 6-2 until 6-7.
please download this file to view it

CLICK TO DOWNLOAD

Digital Arithmetic

This's my task about Digital Arithmetic
This is the question from the book of "Digital System" by Ronald J. Tocci and Neal Widmer
number 6-2
This question has been answered

kilk to Download digital Arithmetic  from Google Drive

Fibonacci up to 15th

Fibonacci Rows up to 15th number.

The script : Fibonacci Script

Triangle Pascal

Script : Triangle Pascal

Script

Proceeds

SYNCROUNOUS UP COUNTER MODULE

click link below

LINK: SYNCROUNOUS UP COUNTER MODULE

Up and Down Counter

this's my task about Up and Down Counter

clik Download below to view it.

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Download Here Up Counter and Down Counter
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Serial Shift Register from Right to Left

I want to show "Serial Shift Register from Right to Left"
please click DOWNLOAD below to view it

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DOWNLOAD
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Timing Diagram

Now
I will show Timing Diagram of  "D Flip-Flop" and "JK Flip-Flop",
click the link below to download and view it !

Timing Diagram

Presentation theory of superposition

this my task about presentation theory of superposition.
click the special mark below to see !!!


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=Presentation theory of superposition=
 ==========================


To download this files on the link above, please press "Ctrl+S" button on your keyboard when you open the page.

Or download via slideshare :

Presentation of Superposition

PRISMA PIRAMIDA with Excel

how to make a pyramid / prism using existing tables in microsoft excel ?

Ok, for more information please click the link below  ^_^ 

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=  prisma piramida =

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Design a logic circuit that will control the horn

A manufacturing plant needs to have a horn sound to signal quitting time. The horn should be activated when either of the following conditions is met:

1. It's after 5 o'clock and all machines are shut down

2. It's Friday, the production run for the day is complete, and all machines are shut down.

Design a logic circuit that will control the horn. (Hint: Use four logic input variables to represent the various conditions; for example , input A will be HIGH only when the time of day is 5 o'clock or later.)

A =  after 5 o'clock

B =  all machines are shut down  it is Friday

C =  production  is complete

D =  all machines are shut down

X  = A/BCD + ABC/D/ + ABC/D + ABCD

This is a link from my excel task about Integral and differential  : Exercise of Ms.Excel

Combinational Logic Circuit

This's my exercise about Combinational Logic Circuit with Kernaugh Map Method. Here I will use the 4 variables (look at point A and point B in the picture) and 3 variables (look at point C in the picture)

Simplify The Following Expressions Using Boolean Algebra

a) X = ABC + A\C\
   Answer :
         = C (AB +A\)
         = C (A\+B)
         = A\C+BC

b) Y = (Q + R) (Q\+R\)
   Answer :      
         = QQ\ + QR\ + Q\R + RR\
         = QR\ + Q\R

c) W = ABC + AB\C + A\
   Answer :       
          = AC (B + B\) + A\
          = AC + A\

d) Q = R\S\T\ (R+S+T)\
   Answer :
        = (RST)\ (R+S+T)\
        = (RST)\+(RST)\+(RST)\
        = (RST)\

e) X = A\B\C\ + A\BC + ABC + AB\C\ + AB\C
   Answer :
        = A\B\C\ + AB\C\ + A\BC + ABC + AB\C
        = B\C\ (A\+A) + BC (A\+A) + AB\C
        = B\C\ + BC +AB\C
        = B\C\ + C (B + AB\)
        = B\C\ + C (B + A)
        = B\C\ + BC + AC
        
f) Z = (B+C\) (B\+C) A\\+B\+C\\
   Answer :
       = BB\ + BC + B\C\ + C\C + AB\C
       = BC + B\C\ + AB\C
       = BC + B\ (C\+AC)
       = BC + B\ (C\+A)
       = BC + B\C\ + AB\

g) Y = (C+D)\ + A\CD\ + AB\C\ + A\B\CD + ACD\
   Answer :
        = C\D\ + A\CD\ + ACD\ + AB\C\ + A\B\CD
        = C\D\ + CD\ (A\ + A) + AB\C\ + A\B\CD
        = C\D\ + CD\ + AB\C\ + A\B\CD
        = D\ (C\+C) + AB\C\ + A\B\CD
        = D\ + AB\C\ + A\B\CD
        = D\ + B\ (AC\+A\CD)
        
h) X = AB (C\D)\ + A\BD + B\C\D\
   Answer :
        = AB (CD\) + A\BD + B\C\D\
        = ABC + ABD\ + A\BD + B\C\D\
        = ABC + A\BD + ABD\ + B\C\D\
        = B (AC+A\D) +  D\ (AB+B\C\)