Presentation theory of superposition

this my task about presentation theory of superposition.
click the special mark below to see !!!


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=Presentation theory of superposition=
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Presentation of Superposition

PRISMA PIRAMIDA with Excel

how to make a pyramid / prism using existing tables in microsoft excel ?

Ok, for more information please click the link below  ^_^ 

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=  prisma piramida =

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Design a logic circuit that will control the horn

A manufacturing plant needs to have a horn sound to signal quitting time. The horn should be activated when either of the following conditions is met:

1. It's after 5 o'clock and all machines are shut down

2. It's Friday, the production run for the day is complete, and all machines are shut down.

Design a logic circuit that will control the horn. (Hint: Use four logic input variables to represent the various conditions; for example , input A will be HIGH only when the time of day is 5 o'clock or later.)

A =  after 5 o'clock

B =  all machines are shut down  it is Friday

C =  production  is complete

D =  all machines are shut down

X  = A/BCD + ABC/D/ + ABC/D + ABCD

This is a link from my excel task about Integral and differential  : Exercise of Ms.Excel

Combinational Logic Circuit

This's my exercise about Combinational Logic Circuit with Kernaugh Map Method. Here I will use the 4 variables (look at point A and point B in the picture) and 3 variables (look at point C in the picture)

Simplify The Following Expressions Using Boolean Algebra

a) X = ABC + A\C\
   Answer :
         = C (AB +A\)
         = C (A\+B)
         = A\C+BC

b) Y = (Q + R) (Q\+R\)
   Answer :      
         = QQ\ + QR\ + Q\R + RR\
         = QR\ + Q\R

c) W = ABC + AB\C + A\
   Answer :       
          = AC (B + B\) + A\
          = AC + A\

d) Q = R\S\T\ (R+S+T)\
   Answer :
        = (RST)\ (R+S+T)\
        = (RST)\+(RST)\+(RST)\
        = (RST)\

e) X = A\B\C\ + A\BC + ABC + AB\C\ + AB\C
   Answer :
        = A\B\C\ + AB\C\ + A\BC + ABC + AB\C
        = B\C\ (A\+A) + BC (A\+A) + AB\C
        = B\C\ + BC +AB\C
        = B\C\ + C (B + AB\)
        = B\C\ + C (B + A)
        = B\C\ + BC + AC
        
f) Z = (B+C\) (B\+C) A\\+B\+C\\
   Answer :
       = BB\ + BC + B\C\ + C\C + AB\C
       = BC + B\C\ + AB\C
       = BC + B\ (C\+AC)
       = BC + B\ (C\+A)
       = BC + B\C\ + AB\

g) Y = (C+D)\ + A\CD\ + AB\C\ + A\B\CD + ACD\
   Answer :
        = C\D\ + A\CD\ + ACD\ + AB\C\ + A\B\CD
        = C\D\ + CD\ (A\ + A) + AB\C\ + A\B\CD
        = C\D\ + CD\ + AB\C\ + A\B\CD
        = D\ (C\+C) + AB\C\ + A\B\CD
        = D\ + AB\C\ + A\B\CD
        = D\ + B\ (AC\+A\CD)
        
h) X = AB (C\D)\ + A\BD + B\C\D\
   Answer :
        = AB (CD\) + A\BD + B\C\D\
        = ABC + ABD\ + A\BD + B\C\D\
        = ABC + A\BD + ABD\ + B\C\D\
        = B (AC+A\D) +  D\ (AB+B\C\)